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Friday, September 27, 2013
Design,develop,and execute a program in C++ to create a class called OCTAL, which has the characteristics of an octal number, Implement the following operations by writing an appropriate constructor and an overloaded operator +.
<![if !supportLists]>1. <![endif]>OCTAL h=x;where x is an integer
<![if !supportLists]>2. <![endif]>Int y=h+k; where h is an OCTAL object and k is an integer.
Display the OCTAL result by overloading the operator<<. Also display the values of h and y.
#include<iostream.h>
#include<conio.h>
class octal
{
int onum;
public:
octal(int);
friend ostream& operator<<(ostream&,octal&);
int operator+(int);
};
octal::octal(int x)
{
//decimal to octal conversion
int base=1,rem;
onum=0;
while(x>0)
{
rem=x%8;
x=x/8;
onum=onum+rem*base;
base=base*10;
}
}
ostream& operator<<(ostream& dout,octal& h)
{
dout<<h.onum;
return dout;
}
octal::operator+(int k)
{
//conversion from octal to conversion
int rem,base=1,dnum=0,y;
while(onum>0)
{
rem=onum%10;
onum=onum/10;
dnum=dnum+rem*base;
base=base*8;
y=dnum+k;
}
return(y);
}
void main()
{
int x,k,y;
clrscr();
cout<<"enter the value of x \n";
cin>>x;
octal h=x;
cout<<"the value of h is"<<h<<endl;
cout<<"enter the value of k \n";
cin>>k;
y=h+k;
cout<<"value of y="<<y;
getch();
}
Screenshot:
Thursday, September 26, 2013
Design, develop and execute a program in C to Evaluate a valid postfix expression using stack. Assume that the postfix expression is read as a single line consisting of non-negative single digit operands and binary arithmetic operators. The arithmetic operators are +(add),-(subtract),*(multiply) and / (divide)
#include<stdio.h>
#include<conio.h>
#include<ctype.h>
#include<math.h>
char postfix[20];
int top=-1;
float value[20],stack[20];
float eval();
void push(float);
float pop();
void main()
{
int i=0;
float result;
clrscr();
printf("enter a valid postfix expression\n");
scanf("%s",postfix);
while(postfix[i]!='\0')
{
if(isalpha(postfix[i]))
{
printf("enter the value of %c\n",postfix[i]);
scanf("%f",&value[i]);
}
i++;
}
result=eval();
printf("the value of the expression is %.2f\n",result);
getch();
}
float eval()
{
int i=0;
float op1,op2,result;
while(postfix[i]!='\0')
{
if(isalpha(postfix[i]))
push(value[i]);
else
{
op2=pop();
op1=pop();
switch(postfix[i])
{
case'+':
push(op1+op2);
break;
case'-':
push(op1-op2);
break;
case'*':
push(op1*op2);
break;
case'/':
push(op1/op2);
break;
};
}
i++;
}
result=pop();
return result;
}
void push(float value)
{
top=top+1;
stack[top]=value;
return;
}
float pop()
{
return stack[top--];
}
Screenshot:
#include<iostream.h>
#include<conio.h>
class student
{
protected:
int rollno;
public:
void getroll()
{
cout<<"enter the roll no"<<endl;
cin>>rollno;
}
};
class marks:public student
{
protected:
int marks;
public:
void getmarks()
{
cout<<"enter the marks"<<endl;
cin>>marks;
}
void display()
{
getroll();
cout<<"roll no:"<<rollno<<endl<<"marks:"<<marks;
}
};
void main()
{
marks b;
clrscr();
b.getmarks();
b.display();
getch();
}
Screenshot:
#include<iostream.h>
#include<conio.h>
class test
{
int x;
int temp;
public:
void operator -();
void read();
void display();
};
void test::operator-()
{
x=-x;
}
void test::read()
{
x=20;
temp=x;
}
void test::display()
{
cout<<"temp="<<temp<<endl;
cout<<x<<endl;
}
void main()
{
test b;
clrscr();
b.read();
-b;
b.display();
getch();
}
Screenshot:
Design,develop and execute the c++ program according to the below instructions:
An employee class is to contain following datamembers and memer functions:
data member:
empolyee_number
employee_name
basic_salary
all_alavances
it(income tax)
net_salary
member functions:
to read data of an emplyee
to calculate salary
to print value of all data memebers
hints:
all_alavances=120% of basic salary
it=30% of gross salary
net salary=basic salary+all_alavances-income tax
gross salary=basic salary+all_alavances
An employee class is to contain following datamembers and memer functions:
data member:
empolyee_number
employee_name
basic_salary
all_alavances
it(income tax)
net_salary
member functions:
to read data of an emplyee
to calculate salary
to print value of all data memebers
hints:
all_alavances=120% of basic salary
it=30% of gross salary
net salary=basic salary+all_alavances-income tax
gross salary=basic salary+all_alavances
---------
#include<iostream.h>
#include<conio.h>
#define MAX 2
class employee
{
int employee_number;
char employee_name[15];
int basic_salary;
int all_alavances;
int it;
int net_salary;
public:
void read()
{
cout<<"enter the employee number"<<endl;
cin>>employee_number;
cout<<"enter the employee name"<<endl;
cin>>employee_name;
cout<<"enter the basic salary"<<endl;
cin>>basic_salary;
}
void calc()
{
int gross;
all_alavances=(basic_salary*120)/100;
gross=basic_salary+all_alavances;
it=(gross*30)/100;
net_salary=gross-it;
cout<<"calaculated"<<endl;
}
void print()
{
cout<<employee_number<<"\t"<<employee_name<<"\t"<<basic_salary<<"\t"<<all_alavances<<"\t"<<it<<"\t"<<net_salary<<endl;
}
};
void main()
{
int i;
employee a[MAX];
clrscr();
for(i=0;i<MAX;i++)
{
a[i].read();
a[i].calc();
}
cout<<"employee number|empolyee name|basic salary|all alavances|income tax"<<"\t"<<"net_salary"<<endl;
for(i=0;i<MAX;i++)
{
a[i].print();
}
getch();
}
#include<iostream.h>
#include<conio.h>
#define MAX 2
class employee
{
int employee_number;
char employee_name[15];
int basic_salary;
int all_alavances;
int it;
int net_salary;
public:
void read()
{
cout<<"enter the employee number"<<endl;
cin>>employee_number;
cout<<"enter the employee name"<<endl;
cin>>employee_name;
cout<<"enter the basic salary"<<endl;
cin>>basic_salary;
}
void calc()
{
int gross;
all_alavances=(basic_salary*120)/100;
gross=basic_salary+all_alavances;
it=(gross*30)/100;
net_salary=gross-it;
cout<<"calaculated"<<endl;
}
void print()
{
cout<<employee_number<<"\t"<<employee_name<<"\t"<<basic_salary<<"\t"<<all_alavances<<"\t"<<it<<"\t"<<net_salary<<endl;
}
};
void main()
{
int i;
employee a[MAX];
clrscr();
for(i=0;i<MAX;i++)
{
a[i].read();
a[i].calc();
}
cout<<"employee number|empolyee name|basic salary|all alavances|income tax"<<"\t"<<"net_salary"<<endl;
for(i=0;i<MAX;i++)
{
a[i].print();
}
getch();
}
Sunday, September 15, 2013
Design,develop and execute a program in C to execute a validpostfix expression using stack. Assume that the postfix expression isread as a single line consisting of non-negative single digit operandsand binary arithematic operators.The arithematic operators are +(add),-(subtract),*(multiply) and /(add).
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#include<stdio.h>
#include<stdlib.h>
#include<string.h>
void infix_postfix(char[],char[]);
char s[30];
int top=-1;
void push(char elem)
{
s[++top]=elem;
}
char pop()
{
return(s[top--]);
}
void main()
{
char infix[20];
char postfix[20];
clrscr();
printf("Enter a valid infix expression\n");
gets(infix);
infix_postfix(infix, postfix);
printf("The postfix expression is\n");
puts(postfix);
getch();
}
void infix_postfix(char infix[],char postfix[])
{
int j;
int i;
char symbol,x;
push('#');
j=0;
for(i=0;i<strlen(infix);i++)
{
symbol=infix[i];
switch(symbol)
{
case'(':
push(symbol);
break;
case ')':
while(s[top]!='(')
{
postfix[j++]=pop();
}
x=pop();
break;
case'/':
case'*':
case'+':
case'-': while(isp(s[top])>=icp(symbol))
{
postfix[j]=pop();
j++;
}
push(symbol);
break;
default:
postfix[j++]=symbol;
break;
}
}
while(s[top]!='#')
{
postfix[j++]=pop();
}
postfix[j]='\0';
}
int isp(char symbol)
{
switch(symbol)
{
case '/':
case '*':return (3);
case '+':
case '-':return (2);
case ')':
case '(':return (1);
case '#':return (-1);
default :return (0);
}
}
int icp(char symbol)
{
switch(symbol)
{
case'/':
case'*':return (3);
case'+':
case'-':return (2);
case'#':return (-1);
default:return (0);
}
}
------
/*Program Ends*/
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